Triangular Load at a Station Calculator
Deflection at station x for a triangular load that is zero at the left support. x = L/2 is the midspan page. Runs locally.
Trust summary CVP VERIFIED · production STALE · CVP protocol 1.0.0-proposed · Engineering assurance · one-sided triangle at station δ = w0[(7L³/360)x−(L/36)x³+x⁵/(120L)]/(EI); + O3 mpmath tabulated δ.
- Input interpretation
- Enter values to calculate.
- Result
- —
- Verified scope
- one-sided triangle at station δ = w0[(7L³/360)x−(L/36)x³+x⁵/(120L)]/(EI); + O3 mpmath tabulated δ.
- Assurance
- Engineering
- Declared partition coverage
- PASS · 5/5 declared partitions (main, alias, signed, awkward, invalid-domain) · Matrix
- Deferred
- Not midspan under the same triangle, and not a cantilever.
- Numerical scope
- O2: delta vs a separate-module identity (≤2 ULP). Not midspan under the same triangle, and not a cantilever. ≤2 ULP vs O3 applies only to the published tabulated triangular-load-at vectors.
- Known limitations
- Core CVP does not include live graph, viewport, or pointer interaction.
- Model
- Deflection at a stated station for a one-sided triangular load on a simply supported span.
- Scope
- Calculation runs locally in the browser; values are not uploaded.
- Verification
- Engine tested · Source checked · v1.0.0 · CVP VERIFIED · production STALE · CVP protocol 1.0.0-proposed · Engineering assurance · one-sided triangle at station δ = w0[(7L³/360)x−(L/36)x³+x⁵/(120L)]/(EI); + O3 mpmath tabulated δ.· View Manifest · CVP overview · Specification
- Versions
- Calculation 1.0.0 · CVP protocol 1.0.0-proposed · Evidence 2026-09-27.o2-o3
- Verification revision
- 2026-09-27.o2-o3 · 1/1 property · digest e8401e119987
- Legacy regression
- 2/2 tests · Production surface contract 6/6
- Trust layers
- Verification VERIFIED · Production STALE · overall VERIFIED_STALE
- CVP status
- STALE · Capability production binding: STALE · Site report: STALE · Evidence changed after the last successful production attestation. Re-attestation required.
- Reference
- O1 model · O3 expected_values · O3 numerical_behavior · O2 expected_values · O2 numerical_behavior
- Interfaces
- PASS · UI (SSR) / REST / MCP
- Supplemental domain review
- Not performed
- Named expert review
- Not performed
- CVP suite
- 4/4 golden · 1/1 CVP boundary · 3/3 invalid · 1/1 property · 1/1 metamorphic · 8/8 O3 · 2/2 cross-interface · 6/6 CVP contract · Manifest
- Sources
- Hibbeler, Mechanics of Materials
- Gere and Goodno, Mechanics of Materials
- Evidence
- 1 legacy golden · 1 legacy boundary · legacy regression suite · 4/4 oracle-backed golden · 3/3 invalid · Artifact integrity PASS
- Semantic contract
- PASS
Full verification
Formulas
Core equations used by this calculator.
How to use
Enter the peak intensity, the station, the span, the modulus, and the area moment
x must lie strictly between the supports, measured from the zero-intensity end.
Read the deflection
The sign of w0 is the sign of δ.
Example calculations
Common configurations with formula and result.
Midspan
w0 = 24, x = 1, L = 2, E = 1, I = 1
Triangular Load at a Station calculator specification
Version 1.0.0 · Engine tested
- Engine tested 2/2 tests · Production surface contract 6/6
- Named expert review Not performed
- Calculation version 1.0.0
- Definition
- A simply supported span carries a triangular load that is 0 at the left support and w0 at the right. At station x from the left, δ = w0 [(7 L³/360) x − (L/36) x³ + x⁵/(120 L)] / (E I).
- What it calculates
- Deflection at a stated station for a one-sided triangular load on a simply supported span.
- Inputs
- w0
- x
- L
- E
- I
- Outputs
- delta
- Formula
δ = w0 [(7 L³/360) x − (L/36) x³ + x⁵/(120 L)] / (E I).- Assumptions
- Calculation runs locally in the browser; values are not uploaded.
- Keep units consistent with the labels on each field.
- x = L/2 recovers 5 w0 L⁴/(768 E I).
- Units
- w0, x, L, E, and I set the deflection unit.
- Boundary conditions
- missing w0, x, L, E, or I → MISSING_REQUIRED_INPUT
- L ≤ 0, E ≤ 0, or I ≤ 0 → VALUE_MUST_BE_POSITIVE
- x ≤ 0 or x ≥ L → INVALID_INPUT
- Example
- w0=24 x=1 L=2 E=1 I=1 → δ=2.5
- Validation cases
2 published on this page · 2/2 tests · Production surface contract 6/6 · View evidence
- w0=24 x=1 L=2 E=1 I=1 → δ=2.5
- x=2 L=2 → INVALID_INPUT
- Sources
- Hibbeler, Mechanics of Materials — Deflection of beams — triangular loadSupports: The curve is zero at both supports and 5 w0 L⁴/(768 E I) at midspan.
- Gere and Goodno, Mechanics of Materials — Deflection of beams — triangular loadSupports: Supports the closed form measured from the zero-intensity end.
- Hibbeler, Mechanics of Materials — Deflection of beams — triangular load
- Calculation version
- 1.0.0
Background
Interpretation and common distinctions.
Find the deflection at a stated station for a triangular load that is zero at the left support.
Agent / API notes
Capability id: mechanical.statics.triangular_load_at_deflection · tool id: triangular-load-at · pin 1.0.0.
{ "w0": 24, "x": 1, "L": 2, "E": 1, "I": 1 }
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Frequently asked questions
Key distinctions behind the calculation.
Does midspan match the triangular-load page?
Yes. x = L/2 gives δ = 2.5 for w0 = 24 and L = 2.