Home Developers CVP Evidence Reproduce

CVP reproduce

mechanical.statics.center_triangle_at_deflection

Independent re-run pack: fixed input vectors, O3 expected values, oracle version, commands, and the last result summary. This is how a reader moves from “CalculatorX says it passed” to “I can reproduce why it passed.”

Identity

Calculation version, protocol version, and evidence revision are distinct.

Calculation version
1.0.0
CVP protocol
1.0.0-proposed · proposed
Evidence revision
2026-09-27.o2-o3
Oracle
O3 · mpmath 1.4.1 · 80 dps
Generator
center-triangle-at-mpmath-o3 · seed 20260927.center-triangle-at-o3
Table SHA-256
bdc01367b2af5bd688d93502619f057c717ee323f119a646c5f75242328fe7a9

Numerical claim

O3 PASS is a tabulated-vector claim, not a whole-domain proof.

O2: delta vs a separate-module identity (≤2 ULP). Not midspan under the same center triangle, and not an end-peaked triangle. ≤2 ULP vs O3 applies only to the published tabulated center-triangle-at vectors.

  • Last O3 run 8 / 8
  • Max error observed 1 ULP
  • Threshold ≤ 2 ULP

Commands

Regenerate the table from the public generator. Independent REST check needs only this page's reproduce.json plus stdlib Python — no repo clone and no mpmath. The CVP runner remains a maintainer command.

Regenerate O3 table
python3 generate-center-triangle-at-o3.py after downloading the public generator next to the table
Repo maintainer path
python3 scripts/lib/cvp/oracles/generate-center-triangle-at-o3.py
Independent REST check
Compare POST /api/v1/calc/center-triangle-at against /developers/cvp/reproduce/center-triangle-at-o3-tables.json after downloading check-math-o3-rest.py next to center-triangle-at-o3-tables.json (or pass --reproduce reproduce.json)
Re-run CVP
npm run cvp:run -- --capability mechanical.statics.center_triangle_at_deflection
REST check
POST https://www.calculatorx.com/api/v1/calc/center-triangle-at with a tabulated input from the table below

Re-running the generator without changing seed or inputs should reproduce table SHA-256 bdc01367b2af5bd688d93502619f057c717ee323f119a646c5f75242328fe7a9. Compare each expected_f64 to the production result within the declared ULP threshold.

Tabulated vectors

Every O3 vector used for the ≤2 ULP claim. Expected values come from the published mpmath table, not from the implementation under test.

IDKindInputsExpected (f64)ActualULPStatus
o3-checkcheck{"w0":"24","x":"1","L":"2","E":"1","I":"1"}{"oracle_layer":"analytic","delta":3.2,"w0":24,"x":1,"L":2,"E":1,"I":1}{"model":"center_triangle_at_deflection","w0":24,"x":1,"L":2,"E":1,"I":1,"delta":3.2,"solver":"center-peaked triangle at a station","convention":"Intensity is 0 at both supports and w0 at midspan. Deflection at x uses the left half and symmetry. x = L/2 is the center-triangle midspan page δ = w0 L⁴/(120 E I)."}0PASS
o3-SISI{"w0":"1000","x":"1","L":"2","E":"200000000000","I":"0.00001"}{"oracle_layer":"analytic","delta":0.00006666666666666667,"w0":1000,"x":1,"L":2,"E":200000000000,"I":0.00001}{"model":"center_triangle_at_deflection","w0":1000,"x":1,"L":2,"E":200000000000,"I":0.00001,"delta":0.00006666666666666667,"solver":"center-peaked triangle at a station","convention":"Intensity is 0 at both supports and w0 at midspan. Deflection at x uses the left half and symmetry. x = L/2 is the center-triangle midspan page δ = w0 L⁴/(120 E I)."}0PASS
o3-aliasalias{"w":"48","span":"2","modulus":"1","Ix":"1","x":"1"}{"oracle_layer":"analytic","delta":6.4,"w0":48,"x":1,"L":2,"E":1,"I":1}{"model":"center_triangle_at_deflection","w0":48,"x":1,"L":2,"E":1,"I":1,"delta":6.4,"solver":"center-peaked triangle at a station","convention":"Intensity is 0 at both supports and w0 at midspan. Deflection at x uses the left half and symmetry. x = L/2 is the center-triangle midspan page δ = w0 L⁴/(120 E I)."}0PASS
o3-awkwardawkward{"w0":"13.7","x":"0.8","L":"2","E":"210000","I":"0.83"}{"oracle_layer":"analytic","delta":0.000009961044941671448,"w0":13.7,"x":0.8,"L":2,"E":210000,"I":0.83}{"model":"center_triangle_at_deflection","w0":13.7,"x":0.8,"L":2,"E":210000,"I":0.83,"delta":0.00000996104494167145,"solver":"center-peaked triangle at a station","convention":"Intensity is 0 at both supports and w0 at midspan. Deflection at x uses the left half and symmetry. x = L/2 is the center-triangle midspan page δ = w0 L⁴/(120 E I)."}1PASS
o3-negsigned{"w0":"-24","x":"1","L":"2","E":"1","I":"1"}{"oracle_layer":"analytic","delta":-3.2,"w0":-24,"x":1,"L":2,"E":1,"I":1}{"model":"center_triangle_at_deflection","w0":-24,"x":1,"L":2,"E":1,"I":1,"delta":-3.2,"solver":"center-peaked triangle at a station","convention":"Intensity is 0 at both supports and w0 at midspan. Deflection at x uses the left half and symmetry. x = L/2 is the center-triangle midspan page δ = w0 L⁴/(120 E I)."}0PASS
o3-smallsmall{"w0":"10","x":"0.5","L":"2","E":"1000","I":"0.01"}{"oracle_layer":"analytic","delta":0.09401041666666667,"w0":10,"x":0.5,"L":2,"E":1000,"I":0.01}{"model":"center_triangle_at_deflection","w0":10,"x":0.5,"L":2,"E":1000,"I":0.01,"delta":0.09401041666666667,"solver":"center-peaked triangle at a station","convention":"Intensity is 0 at both supports and w0 at midspan. Deflection at x uses the left half and symmetry. x = L/2 is the center-triangle midspan page δ = w0 L⁴/(120 E I)."}0PASS
o3-stiffstiff{"w0":"500","x":"1","L":"2","E":"210e9","I":"2e-4"}{"oracle_layer":"analytic","delta":0.0000015873015873015873,"w0":500,"x":1,"L":2,"E":210000000000,"I":0.0002}{"model":"center_triangle_at_deflection","w0":500,"x":1,"L":2,"E":210000000000,"I":0.0002,"delta":0.0000015873015873015873,"solver":"center-peaked triangle at a station","convention":"Intensity is 0 at both supports and w0 at midspan. Deflection at x uses the left half and symmetry. x = L/2 is the center-triangle midspan page δ = w0 L⁴/(120 E I)."}0PASS
o3-longlong{"w0":"200","x":"1","L":"4","E":"70e9","I":"5e-5"}{"oracle_layer":"analytic","delta":0.00008595238095238095,"w0":200,"x":1,"L":4,"E":70000000000,"I":0.00005}{"model":"center_triangle_at_deflection","w0":200,"x":1,"L":4,"E":70000000000,"I":0.00005,"delta":0.00008595238095238095,"solver":"center-peaked triangle at a station","convention":"Intensity is 0 at both supports and w0 at midspan. Deflection at x uses the left half and symmetry. x = L/2 is the center-triangle midspan page δ = w0 L⁴/(120 E I)."}0PASS