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CVP reproduce

mechanical.statics.center_triangle_deflection

Independent re-run pack: fixed input vectors, O3 expected values, oracle version, commands, and the last result summary. This is how a reader moves from “CalculatorX says it passed” to “I can reproduce why it passed.”

Identity

Calculation version, protocol version, and evidence revision are distinct.

Calculation version
1.0.0
CVP protocol
1.0.0-proposed · proposed
Evidence revision
2026-09-27.o2-o3
Oracle
O3 · mpmath 1.4.1 · 80 dps
Generator
center-triangle-deflection-mpmath-o3 · seed 20260927.center-triangle-deflection-o3
Table SHA-256
aa00ad809b698744a1a444862dfd34403e32974dc43be30b56f153e0c366c598

Numerical claim

O3 PASS is a tabulated-vector claim, not a whole-domain proof.

O2: delta vs a separate-module identity (≤2 ULP). Not one-sided triangle, not a cantilever, and not a station curve. ≤2 ULP vs O3 applies only to the published tabulated center-triangle-deflection vectors.

  • Last O3 run 8 / 8
  • Max error observed 1 ULP
  • Threshold ≤ 2 ULP

Commands

Regenerate the table from the public generator. Independent REST check needs only this page's reproduce.json plus stdlib Python — no repo clone and no mpmath. The CVP runner remains a maintainer command.

Regenerate O3 table
python3 generate-center-triangle-deflection-o3.py after downloading the public generator next to the table
Repo maintainer path
python3 scripts/lib/cvp/oracles/generate-center-triangle-deflection-o3.py
Independent REST check
Compare POST /api/v1/calc/center-triangle-deflection against /developers/cvp/reproduce/center-triangle-deflection-o3-tables.json after downloading check-math-o3-rest.py next to center-triangle-deflection-o3-tables.json (or pass --reproduce reproduce.json)
Re-run CVP
npm run cvp:run -- --capability mechanical.statics.center_triangle_deflection
REST check
POST https://www.calculatorx.com/api/v1/calc/center-triangle-deflection with a tabulated input from the table below

Re-running the generator without changing seed or inputs should reproduce table SHA-256 aa00ad809b698744a1a444862dfd34403e32974dc43be30b56f153e0c366c598. Compare each expected_f64 to the production result within the declared ULP threshold.

Tabulated vectors

Every O3 vector used for the ≤2 ULP claim. Expected values come from the published mpmath table, not from the implementation under test.

IDKindInputsExpected (f64)ActualULPStatus
o3-checkcheck{"w0":"120","L":"1","E":"1","I":"1"}{"oracle_layer":"analytic","delta":1,"w0":120,"L":1,"E":1,"I":1}{"model":"center_triangle_deflection","w0":120,"L":1,"E":1,"I":1,"delta":1,"solver":"simply supported center-peaked triangle","convention":"Simply supported span. Intensity is 0 at both supports and w0 at midspan. Midspan δ = w0 L⁴/(120 E I), and that is also the largest deflection. Positive w0 is the positive deflection direction. I is an input. The load that is w0 at both ends and 0 at midspan is its own page."}0PASS
o3-SISI{"w0":"1000","L":"2","E":"200e9","I":"1e-5"}{"oracle_layer":"analytic","delta":0.00006666666666666667,"w0":1000,"L":2,"E":200000000000,"I":0.00001}{"model":"center_triangle_deflection","w0":1000,"L":2,"E":200000000000,"I":0.00001,"delta":0.00006666666666666666,"solver":"simply supported center-peaked triangle","convention":"Simply supported span. Intensity is 0 at both supports and w0 at midspan. Midspan δ = w0 L⁴/(120 E I), and that is also the largest deflection. Positive w0 is the positive deflection direction. I is an input. The load that is w0 at both ends and 0 at midspan is its own page."}1PASS
o3-aliasalias{"w":"240","span":"1","modulus":"1","Ix":"1"}{"oracle_layer":"analytic","delta":2,"w0":240,"L":1,"E":1,"I":1}{"model":"center_triangle_deflection","w0":240,"L":1,"E":1,"I":1,"delta":2,"solver":"simply supported center-peaked triangle","convention":"Simply supported span. Intensity is 0 at both supports and w0 at midspan. Midspan δ = w0 L⁴/(120 E I), and that is also the largest deflection. Positive w0 is the positive deflection direction. I is an input. The load that is w0 at both ends and 0 at midspan is its own page."}0PASS
o3-awkwardawkward{"w0":"13.7","L":"3.5","E":"210000","I":"0.83"}{"oracle_layer":"analytic","delta":0.00009829108099062919,"w0":13.7,"L":3.5,"E":210000,"I":0.83}{"model":"center_triangle_deflection","w0":13.7,"L":3.5,"E":210000,"I":0.83,"delta":0.00009829108099062917,"solver":"simply supported center-peaked triangle","convention":"Simply supported span. Intensity is 0 at both supports and w0 at midspan. Midspan δ = w0 L⁴/(120 E I), and that is also the largest deflection. Positive w0 is the positive deflection direction. I is an input. The load that is w0 at both ends and 0 at midspan is its own page."}1PASS
o3-negsigned{"w0":"-120","L":"1","E":"1","I":"1"}{"oracle_layer":"analytic","delta":-1,"w0":-120,"L":1,"E":1,"I":1}{"model":"center_triangle_deflection","w0":-120,"L":1,"E":1,"I":1,"delta":-1,"solver":"simply supported center-peaked triangle","convention":"Simply supported span. Intensity is 0 at both supports and w0 at midspan. Midspan δ = w0 L⁴/(120 E I), and that is also the largest deflection. Positive w0 is the positive deflection direction. I is an input. The load that is w0 at both ends and 0 at midspan is its own page."}0PASS
o3-smallsmall{"w0":"10","L":"1","E":"1000","I":"0.01"}{"oracle_layer":"analytic","delta":0.008333333333333333,"w0":10,"L":1,"E":1000,"I":0.01}{"model":"center_triangle_deflection","w0":10,"L":1,"E":1000,"I":0.01,"delta":0.008333333333333333,"solver":"simply supported center-peaked triangle","convention":"Simply supported span. Intensity is 0 at both supports and w0 at midspan. Midspan δ = w0 L⁴/(120 E I), and that is also the largest deflection. Positive w0 is the positive deflection direction. I is an input. The load that is w0 at both ends and 0 at midspan is its own page."}0PASS
o3-stiffstiff{"w0":"500","L":"1.5","E":"210e9","I":"2e-4"}{"oracle_layer":"analytic","delta":5.022321428571429e-7,"w0":500,"L":1.5,"E":210000000000,"I":0.0002}{"model":"center_triangle_deflection","w0":500,"L":1.5,"E":210000000000,"I":0.0002,"delta":5.022321428571429e-7,"solver":"simply supported center-peaked triangle","convention":"Simply supported span. Intensity is 0 at both supports and w0 at midspan. Midspan δ = w0 L⁴/(120 E I), and that is also the largest deflection. Positive w0 is the positive deflection direction. I is an input. The load that is w0 at both ends and 0 at midspan is its own page."}0PASS
o3-longlong{"w0":"200","L":"4","E":"70e9","I":"5e-5"}{"oracle_layer":"analytic","delta":0.0001219047619047619,"w0":200,"L":4,"E":70000000000,"I":0.00005}{"model":"center_triangle_deflection","w0":200,"L":4,"E":70000000000,"I":0.00005,"delta":0.0001219047619047619,"solver":"simply supported center-peaked triangle","convention":"Simply supported span. Intensity is 0 at both supports and w0 at midspan. Midspan δ = w0 L⁴/(120 E I), and that is also the largest deflection. Positive w0 is the positive deflection direction. I is an input. The load that is w0 at both ends and 0 at midspan is its own page."}0PASS