CVP reproduce
Independent re-run pack: fixed input vectors, O3 expected values, oracle version, commands, and the last result summary. This is how a reader moves from “CalculatorX says it passed” to “I can reproduce why it passed.”
Calculation version, protocol version, and evidence revision are distinct.
O3 PASS is a tabulated-vector claim, not a whole-domain proof.
O2: delta vs a separate-module identity (≤2 ULP). Not the max-deflection station page, not a cantilever, and not center-peaked triangle. ≤2 ULP vs O3 applies only to the published tabulated triangular-load-deflection vectors.
Regenerate the table from the public generator. Independent REST check needs only this page's reproduce.json plus stdlib Python — no repo clone and no mpmath. The CVP runner remains a maintainer command.
Re-running the generator without changing seed or inputs should reproduce table SHA-256 a9f609018aae9a3cf30813b0aa535abde7167a7839225a8de5ad123f92ffe701. Compare each expected_f64 to the production result within the declared ULP threshold.
Every O3 vector used for the ≤2 ULP claim. Expected values come from the published mpmath table, not from the implementation under test.
| ID | Kind | Inputs | Expected (f64) | Actual | ULP | Status |
|---|---|---|---|---|---|---|
o3-check | check | {"w0":"24","L":"2","E":"1","I":"1"} | {"oracle_layer":"analytic","delta":2.5,"w0":24,"L":2,"E":1,"I":1} | {"model":"triangular_load_deflection","w0":24,"L":2,"E":1,"I":1,"delta":2.5,"solver":"simply supported triangular load midspan","convention":"Simply supported span. Intensity is 0 at the left support and w0 at the right. Midspan δ = 5 w0 L⁴/(768 E I). That equals a uniform load of intensity w0/2. Positive w0 is the positive deflection direction. I is an input. The largest deflection is not at midspan."} | 0 | PASS |
o3-SI | SI | {"w0":"1000","L":"2","E":"200e9","I":"1e-5"} | {"oracle_layer":"analytic","delta":0.00005208333333333334,"w0":1000,"L":2,"E":200000000000,"I":0.00001} | {"model":"triangular_load_deflection","w0":1000,"L":2,"E":200000000000,"I":0.00001,"delta":0.00005208333333333332,"solver":"simply supported triangular load midspan","convention":"Simply supported span. Intensity is 0 at the left support and w0 at the right. Midspan δ = 5 w0 L⁴/(768 E I). That equals a uniform load of intensity w0/2. Positive w0 is the positive deflection direction. I is an input. The largest deflection is not at midspan."} | 2 | PASS |
o3-alias | alias | {"w":"48","span":"2","modulus":"1","Ix":"1"} | {"oracle_layer":"analytic","delta":5,"w0":48,"L":2,"E":1,"I":1} | {"model":"triangular_load_deflection","w0":48,"L":2,"E":1,"I":1,"delta":5,"solver":"simply supported triangular load midspan","convention":"Simply supported span. Intensity is 0 at the left support and w0 at the right. Midspan δ = 5 w0 L⁴/(768 E I). That equals a uniform load of intensity w0/2. Positive w0 is the positive deflection direction. I is an input. The largest deflection is not at midspan."} | 0 | PASS |
o3-awkward | awkward | {"w0":"13.7","L":"2","E":"210000","I":"0.83"} | {"oracle_layer":"analytic","delta":0.000008187511952572193,"w0":13.7,"L":2,"E":210000,"I":0.83} | {"model":"triangular_load_deflection","w0":13.7,"L":2,"E":210000,"I":0.83,"delta":0.000008187511952572193,"solver":"simply supported triangular load midspan","convention":"Simply supported span. Intensity is 0 at the left support and w0 at the right. Midspan δ = 5 w0 L⁴/(768 E I). That equals a uniform load of intensity w0/2. Positive w0 is the positive deflection direction. I is an input. The largest deflection is not at midspan."} | 0 | PASS |
o3-neg | signed | {"w0":"-24","L":"2","E":"1","I":"1"} | {"oracle_layer":"analytic","delta":-2.5,"w0":-24,"L":2,"E":1,"I":1} | {"model":"triangular_load_deflection","w0":-24,"L":2,"E":1,"I":1,"delta":-2.5,"solver":"simply supported triangular load midspan","convention":"Simply supported span. Intensity is 0 at the left support and w0 at the right. Midspan δ = 5 w0 L⁴/(768 E I). That equals a uniform load of intensity w0/2. Positive w0 is the positive deflection direction. I is an input. The largest deflection is not at midspan."} | 0 | PASS |
o3-small | small | {"w0":"10","L":"2","E":"1000","I":"0.01"} | {"oracle_layer":"analytic","delta":0.10416666666666667,"w0":10,"L":2,"E":1000,"I":0.01} | {"model":"triangular_load_deflection","w0":10,"L":2,"E":1000,"I":0.01,"delta":0.10416666666666667,"solver":"simply supported triangular load midspan","convention":"Simply supported span. Intensity is 0 at the left support and w0 at the right. Midspan δ = 5 w0 L⁴/(768 E I). That equals a uniform load of intensity w0/2. Positive w0 is the positive deflection direction. I is an input. The largest deflection is not at midspan."} | 0 | PASS |
o3-stiff | stiff | {"w0":"500","L":"2","E":"210e9","I":"2e-4"} | {"oracle_layer":"analytic","delta":0.000001240079365079365,"w0":500,"L":2,"E":210000000000,"I":0.0002} | {"model":"triangular_load_deflection","w0":500,"L":2,"E":210000000000,"I":0.0002,"delta":0.000001240079365079365,"solver":"simply supported triangular load midspan","convention":"Simply supported span. Intensity is 0 at the left support and w0 at the right. Midspan δ = 5 w0 L⁴/(768 E I). That equals a uniform load of intensity w0/2. Positive w0 is the positive deflection direction. I is an input. The largest deflection is not at midspan."} | 0 | PASS |
o3-long | long | {"w0":"200","L":"4","E":"70e9","I":"5e-5"} | {"oracle_layer":"analytic","delta":0.00009523809523809524,"w0":200,"L":4,"E":70000000000,"I":0.00005} | {"model":"triangular_load_deflection","w0":200,"L":4,"E":70000000000,"I":0.00005,"delta":0.00009523809523809524,"solver":"simply supported triangular load midspan","convention":"Simply supported span. Intensity is 0 at the left support and w0 at the right. Midspan δ = 5 w0 L⁴/(768 E I). That equals a uniform load of intensity w0/2. Positive w0 is the positive deflection direction. I is an input. The largest deflection is not at midspan."} | 0 | PASS |
