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CVP reproduce

mechanical.statics.uniform_load_deflection

Independent re-run pack: fixed input vectors, O3 expected values, oracle version, commands, and the last result summary. This is how a reader moves from “CalculatorX says it passed” to “I can reproduce why it passed.”

Identity

Calculation version, protocol version, and evidence revision are distinct.

Calculation version
1.0.0
CVP protocol
1.0.0-proposed · proposed
Evidence revision
2026-09-27.o2-o3
Oracle
O3 · mpmath 1.4.1 · 80 dps
Generator
uniform-load-deflection-mpmath-o3 · seed 20260927.uniform-load-deflection-o3
Table SHA-256
902e6b37c0f601b7cc5dc6feb7259fd096e057f2ca4fba77aed1188b802350ab

Numerical claim

O3 PASS is a tabulated-vector claim, not a whole-domain proof.

O2: delta vs a separate-module identity (≤2 ULP). Not a cantilever, not a concentrated load, and not an intermediate station. ≤2 ULP vs O3 applies only to the published tabulated uniform-load-deflection vectors.

  • Last O3 run 8 / 8
  • Max error observed 2 ULP
  • Threshold ≤ 2 ULP

Commands

Regenerate the table from the public generator. Independent REST check needs only this page's reproduce.json plus stdlib Python — no repo clone and no mpmath. The CVP runner remains a maintainer command.

Regenerate O3 table
python3 generate-uniform-load-deflection-o3.py after downloading the public generator next to the table
Repo maintainer path
python3 scripts/lib/cvp/oracles/generate-uniform-load-deflection-o3.py
Independent REST check
Compare POST /api/v1/calc/uniform-load-deflection against /developers/cvp/reproduce/uniform-load-deflection-o3-tables.json after downloading check-math-o3-rest.py next to uniform-load-deflection-o3-tables.json (or pass --reproduce reproduce.json)
Re-run CVP
npm run cvp:run -- --capability mechanical.statics.uniform_load_deflection
REST check
POST https://www.calculatorx.com/api/v1/calc/uniform-load-deflection with a tabulated input from the table below

Re-running the generator without changing seed or inputs should reproduce table SHA-256 902e6b37c0f601b7cc5dc6feb7259fd096e057f2ca4fba77aed1188b802350ab. Compare each expected_f64 to the production result within the declared ULP threshold.

Tabulated vectors

Every O3 vector used for the ≤2 ULP claim. Expected values come from the published mpmath table, not from the implementation under test.

IDKindInputsExpected (f64)ActualULPStatus
o3-checkcheck{"w":"384","L":"1","E":"1","I":"1"}{"oracle_layer":"analytic","delta":5,"w":384,"L":1,"E":1,"I":1}{"model":"uniform_load_deflection","w":384,"L":1,"E":1,"I":1,"delta":5,"solver":"simply supported uniform load","convention":"Simply supported span with a uniform load over the whole span. Midspan δ = 5 w L⁴/(384 E I). Positive w is the positive deflection direction. I is an input. A cantilever and a concentrated load are their own pages."}0PASS
o3-SISI{"w":"1000","L":"2","E":"200e9","I":"1e-5"}{"oracle_layer":"analytic","delta":0.00010416666666666667,"w":1000,"L":2,"E":200000000000,"I":0.00001}{"model":"uniform_load_deflection","w":1000,"L":2,"E":200000000000,"I":0.00001,"delta":0.00010416666666666665,"solver":"simply supported uniform load","convention":"Simply supported span with a uniform load over the whole span. Midspan δ = 5 w L⁴/(384 E I). Positive w is the positive deflection direction. I is an input. A cantilever and a concentrated load are their own pages."}2PASS
o3-aliasalias{"intensity":"768","span":"1","modulus":"1","Ix":"1"}{"oracle_layer":"analytic","delta":10,"w":768,"L":1,"E":1,"I":1}{"model":"uniform_load_deflection","w":768,"L":1,"E":1,"I":1,"delta":10,"solver":"simply supported uniform load","convention":"Simply supported span with a uniform load over the whole span. Midspan δ = 5 w L⁴/(384 E I). Positive w is the positive deflection direction. I is an input. A cantilever and a concentrated load are their own pages."}0PASS
o3-awkwardawkward{"w":"13.7","L":"3.5","E":"210000","I":"0.83"}{"oracle_layer":"analytic","delta":0.0001535798140478581,"w":13.7,"L":3.5,"E":210000,"I":0.83}{"model":"uniform_load_deflection","w":13.7,"L":3.5,"E":210000,"I":0.83,"delta":0.0001535798140478581,"solver":"simply supported uniform load","convention":"Simply supported span with a uniform load over the whole span. Midspan δ = 5 w L⁴/(384 E I). Positive w is the positive deflection direction. I is an input. A cantilever and a concentrated load are their own pages."}0PASS
o3-negsigned{"w":"-384","L":"1","E":"1","I":"1"}{"oracle_layer":"analytic","delta":-5,"w":-384,"L":1,"E":1,"I":1}{"model":"uniform_load_deflection","w":-384,"L":1,"E":1,"I":1,"delta":-5,"solver":"simply supported uniform load","convention":"Simply supported span with a uniform load over the whole span. Midspan δ = 5 w L⁴/(384 E I). Positive w is the positive deflection direction. I is an input. A cantilever and a concentrated load are their own pages."}0PASS
o3-smallsmall{"w":"10","L":"1","E":"1000","I":"0.01"}{"oracle_layer":"analytic","delta":0.013020833333333334,"w":10,"L":1,"E":1000,"I":0.01}{"model":"uniform_load_deflection","w":10,"L":1,"E":1000,"I":0.01,"delta":0.013020833333333334,"solver":"simply supported uniform load","convention":"Simply supported span with a uniform load over the whole span. Midspan δ = 5 w L⁴/(384 E I). Positive w is the positive deflection direction. I is an input. A cantilever and a concentrated load are their own pages."}0PASS
o3-stiffstiff{"w":"500","L":"1.5","E":"210e9","I":"2e-4"}{"oracle_layer":"analytic","delta":7.847377232142857e-7,"w":500,"L":1.5,"E":210000000000,"I":0.0002}{"model":"uniform_load_deflection","w":500,"L":1.5,"E":210000000000,"I":0.0002,"delta":7.847377232142857e-7,"solver":"simply supported uniform load","convention":"Simply supported span with a uniform load over the whole span. Midspan δ = 5 w L⁴/(384 E I). Positive w is the positive deflection direction. I is an input. A cantilever and a concentrated load are their own pages."}0PASS
o3-longlong{"w":"200","L":"4","E":"70e9","I":"5e-5"}{"oracle_layer":"analytic","delta":0.00019047619047619048,"w":200,"L":4,"E":70000000000,"I":0.00005}{"model":"uniform_load_deflection","w":200,"L":4,"E":70000000000,"I":0.00005,"delta":0.00019047619047619048,"solver":"simply supported uniform load","convention":"Simply supported span with a uniform load over the whole span. Midspan δ = 5 w L⁴/(384 E I). Positive w is the positive deflection direction. I is an input. A cantilever and a concentrated load are their own pages."}0PASS