Triangular Load Deflection Calculator
Midspan deflection of a simply supported span with a triangular load. δ = 5 w0 L⁴ / (768 E I). Intensity is 0 at the left support. Runs locally.
Trust summary CVP VERIFIED · production STALE · CVP protocol 1.0.0-proposed · Engineering assurance · one-sided triangle midspan δ = 5 w0 L⁴/(768 E I); + O3 mpmath tabulated δ.
- Input interpretation
- Enter values to calculate.
- Result
- —
- Verified scope
- one-sided triangle midspan δ = 5 w0 L⁴/(768 E I); + O3 mpmath tabulated δ.
- Assurance
- Engineering
- Declared partition coverage
- PASS · 5/5 declared partitions (main, alias, signed, awkward, invalid-domain) · Matrix
- Deferred
- Not the max-deflection station page, not a cantilever, and not center-peaked triangle.
- Numerical scope
- O2: delta vs a separate-module identity (≤2 ULP). Not the max-deflection station page, not a cantilever, and not center-peaked triangle. ≤2 ULP vs O3 applies only to the published tabulated triangular-load-deflection vectors.
- Known limitations
- Core CVP does not include live graph, viewport, or pointer interaction.
- Model
- Midspan deflection of a simply supported span under a triangular load that is zero at the left support.
- Scope
- Calculation runs locally in the browser; values are not uploaded.
- Verification
- Engine tested · Source checked · v1.0.0 · CVP VERIFIED · production STALE · CVP protocol 1.0.0-proposed · Engineering assurance · one-sided triangle midspan δ = 5 w0 L⁴/(768 E I); + O3 mpmath tabulated δ.· View Manifest · CVP overview · Specification
- Versions
- Calculation 1.0.0 · CVP protocol 1.0.0-proposed · Evidence 2026-09-27.o2-o3
- Verification revision
- 2026-09-27.o2-o3 · 1/1 property · digest ecf46228005a
- Legacy regression
- 3/3 tests · Production surface contract 6/6
- Trust layers
- Verification VERIFIED · Production STALE · overall VERIFIED_STALE
- CVP status
- STALE · Capability production binding: STALE · Site report: STALE · Evidence changed after the last successful production attestation. Re-attestation required.
- Reference
- O1 model · O3 expected_values · O3 numerical_behavior · O2 expected_values · O2 numerical_behavior
- Interfaces
- PASS · UI (SSR) / REST / MCP
- Supplemental domain review
- Not performed
- Named expert review
- Not performed
- CVP suite
- 4/4 golden · 1/1 CVP boundary · 3/3 invalid · 1/1 property · 1/1 metamorphic · 8/8 O3 · 2/2 cross-interface · 6/6 CVP contract · Manifest
- Sources
- Hibbeler, Mechanics of Materials
- Gere and Goodno, Mechanics of Materials
- Evidence
- 2 legacy golden · 1 legacy boundary · legacy regression suite · 4/4 oracle-backed golden · 3/3 invalid · Artifact integrity PASS
- Semantic contract
- PASS
Full verification
Formulas
Core equations used by this calculator.
How to use
Enter the peak intensity, the span, the modulus, and the area moment
L, E, and I must be positive. w0 may be negative.
Read the midspan deflection
The sign of w0 is the sign of δ.
Example calculations
Common configurations with formula and result.
Peak of 24 on a span of 2
w0 = 24, L = 2, E = 1, I = 1
Triangular Load Deflection calculator specification
Version 1.0.0 · Engine tested
- Engine tested 3/3 tests · Production surface contract 6/6
- Named expert review Not performed
- Calculation version 1.0.0
- Definition
- A simply supported span of length L carries a triangular load that is 0 at the left support and w0 at the right. The midspan deflection is δ = 5 w0 L⁴ / (768 E I).
- What it calculates
- Midspan deflection of a simply supported span under a triangular load that is zero at the left support.
- Inputs
- w0
- L
- E
- I
- Outputs
- delta
- Formula
δ = 5 w0 L⁴ / (768 E I).- Assumptions
- Calculation runs locally in the browser; values are not uploaded.
- Keep units consistent with the labels on each field.
- This equals a uniform load of intensity w0/2. The largest deflection is not at midspan and is not this page.
- Units
- w0, L, E, and I set the deflection unit.
- Boundary conditions
- missing w0, L, E, or I → MISSING_REQUIRED_INPUT
- L ≤ 0, E ≤ 0, or I ≤ 0 → VALUE_MUST_BE_POSITIVE
- Example
- w0=24 L=2 E=1 I=1 → δ=2.5
- Validation cases
2 published on this page · 3/3 tests · Production surface contract 6/6 · View evidence
- w0=24 L=2 E=1 I=1 → δ=2.5
- L=0 → VALUE_MUST_BE_POSITIVE
- Sources
- Hibbeler, Mechanics of Materials — Deflection of beams — simply supported beam with a triangular loadSupports: Midspan δ = 5 w0 L⁴ / (768 E I) when the intensity is zero at one end and w0 at the other.
- Gere and Goodno, Mechanics of Materials — Deflection of beams — triangular loadSupports: Supports the page formula. The same midspan number is a uniform load of intensity w0/2.
- Hibbeler, Mechanics of Materials — Deflection of beams — simply supported beam with a triangular load
- Calculation version
- 1.0.0
Background
Interpretation and common distinctions.
Find the midspan deflection of a simply supported span under a triangular load. Intensity is 0 at the left support and w0 at the right.
Supported and not supported
Supported: δ = 5 w0 L⁴ / (768 E I). That is the same midspan number as a uniform load of intensity w0/2.
Not supported: the off-midspan maximum, a cantilever, and a point load. /calc/mechanical is not open.
Agent / API notes
Capability id: mechanical.statics.triangular_load_deflection · tool id: triangular-load-deflection · pin 1.0.0.
{ "w0": 24, "L": 2, "E": 1, "I": 1 }
Related tools
Other calculators in this family: Beam Deflection Calculator, Beam Moment Deflection Calculator, Beam Moment Maximum Deflection Calculator, Cantilever Deflection Calculator, Cantilever Intermediate Deflection Calculator, Cantilever Load at a Station Calculator, Cantilever Moment at the Couple Calculator, Cantilever Moment Deflection Calculator . Explore all Beams & Deflection.
Frequently asked questions
Key distinctions behind the calculation.
Is the peak at midspan?
No. The load is heavier toward the right support, so the largest deflection sits a little to the right of midspan. That value is a different page.